(2k+1)(k^2+4k+4)=0

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Solution for (2k+1)(k^2+4k+4)=0 equation: 


Simplifying
(2k + 1)(k2 + 4k + 4) = 0

Reorder the terms:
(1 + 2k)(k2 + 4k + 4) = 0

Reorder the terms:
(1 + 2k)(4 + 4k + k2) = 0

Multiply (1 + 2k) * (4 + 4k + k2)
(1(4 + 4k + k2) + 2k * (4 + 4k + k2)) = 0
((4 * 1 + 4k * 1 + k2 * 1) + 2k * (4 + 4k + k2)) = 0
((4 + 4k + 1k2) + 2k * (4 + 4k + k2)) = 0
(4 + 4k + 1k2 + (4 * 2k + 4k * 2k + k2 * 2k)) = 0
(4 + 4k + 1k2 + (8k + 8k2 + 2k3)) = 0

Reorder the terms:
(4 + 4k + 8k + 1k2 + 8k2 + 2k3) = 0

Combine like terms: 4k + 8k = 12k
(4 + 12k + 1k2 + 8k2 + 2k3) = 0

Combine like terms: 1k2 + 8k2 = 9k2
(4 + 12k + 9k2 + 2k3) = 0

Solving
4 + 12k + 9k2 + 2k3 = 0

Solving for variable 'k'.

The solution to this equation could not be determined.

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